-3w^2-7w+6=0

Solution for -3w^2-7w+6=0 equation:

-3w^2-7w+6=0

a = -3; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·(-3)·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-11}{2*-3}=\frac{-4}{-6}
=2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+11}{2*-3}=\frac{18}{-6}
=-3
$